Question 604734
For a certain game of chance, a player loses $3 with a probability of 0.3, breaks even with probability 0.3, gains $1 with probability 0.2, gains $2 with probability 0.1, and gains $3 with probability 0.1. 
) A player plays the game of chance. What is the probability that a player will win some money? Show work.
P(winning) = 0.2+0.1 = 0.3
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) If the player plays the game many times, what is the player’s expectation? 
E(x) = -3*0.3 + 0*3 +1*0.2 + 2*0.1 + 3*0.1 
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= -0.9 + 0 + 0.2 + 0.2 + 0.3
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= -0.9 + 0.7
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= -0.2
Means the player can expect to lose 20 cents each time he plays the game.
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cheers,
Stan H.
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