Question 604629
Solve the equation: 
4x^3+3x^2=64x+48
Try grouping
x^2(4x+3)=16(4x+3)
set to zero
x^2(4x+3)-16(4x+3)=0
factor out (4x+3)
(4x+3)(x^2-16)=0
solve for x
4x+3=0
4x=-3
x=-3/4
or
x^2-16=0
(x+4)(x-4)=0 (difference of squares)
x=-4
and
x=4
roots or zeros are: -3/4, -4 and 4