Question 604411
assume that the frame has width of x inches
Picture's width = 30 - 2x (x on both sides)
Picture's length = 40 - 2x (x on both sides)


(30 - 2x)*(40 - 2x) = 936
{{{1200 - 60x - 80x + 4x^2 = 936}}}
{{{4x^2 - 140x + 1200 = 936}}}
{{{4x^2 - 140x + 1200 - 936 = 0}}}
{{{4x^2 - 140x + 264 = 0}}}
(divide all by 4)
{{{x^2 - 35x + 66 = 0}}}
(x - 33)*(x - 2) = 0
x - 33 = 0 or x - 2 = 0
x = 33 or x = 2


because the width of the frame can't be 33 (the picture's width and length will be negative if x = 33), then we take x = 2


so, the width of the frame that surrounds the picture is 2 inches