Question 604353
The Vertex of the parabola below is at the point (6, 1.5) and the point (7, 3.5) is on the parabola. what is the equation of the parabola?
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Assuming the parabola is opening upward (it could be to the right),
use the vertex-form:
(x-h)^2 = 4p(y-k)
Substitute for x,y,h,k and solve for "p":
(7-6)^2 = 4p(3.5-1.5)
1 = 4p(2)
4p = 1/2
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Equation:
(x-6)^2 = (1/2)(y-(3/2))
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y = 2[x^2-12x+36]+(3/2)
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y = 2x^2-24x+73.5
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Cheers,
Stan H.