Question 604301
for trip 1 
distance = 84
speed : x
time t1
for tripe 2 :
distance = 22
speed = x-5
time = t2
t1+t2 =2
v =d/t
t = d/v
84/x + 22/(x-5) =2
84 (x-5) +22x = 2x(x-5)
x^2 - 58 x +210 = 0
x = 54.12 mph part 1 
x-5 = 49.12 mph part 2