Question 603831
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
log28=log4+logx
log28-log4=logx
log(28/4) =logx
log (7) = logx
    7 = x 
Rules governing Logarithms:
*[tex \large \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]****
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]