Question 56132
Let g be a linear function. If g(1)=3 and g(-4)=c, find the value of the constant c such that the line will have a slope equal to -1.
:
The formula for the slope is:{{{m=(g(x2)-g(x1))/(x2-x1)}}}
{{{-1=(c-3)/(-4-1))}}}
{{{-1=(c-3)/(-4-1)}}}
{{{-1=(c-3)/-5}}}
{{{-5(-1)=(-5)(c-3)/-5}}}
{{{5=c-3}}}
{{{3+5=c-3+3}}}
{{{highlight(8=c)}}}
:
Check:
{{{-1=(8-3)/(-4-1)}}}
{{{-1=5/-5}}}
{{{-1=-1}}}  Looks good.
:
For the second one.
12x-45=-{48-12x+3}
12x-45=-{51-12x}
12x-45=-51+12x
-12x+12x-45=51+12x-12x
-45=51
You ran out of variables and the sides aren't =, therefore there is no solution.

Happy Calculating!!!