Question 603689
{{{x-5x^(1/2)+4=0}}}


{{{x+4=-5x^(1/2)}}}

square both sides

{{{(x+4)^2=25x}}}


{{{x^2+8x+16=25x}}}


{{{x^2-17x+16=0}}}

{{{x^2-16x-x+16=0}}}

x(x-16)-1(x-16)=0
(x-1)(x-16)=0

x= 1 OR 16