Question 603486
this is a binomial probability ___ either 7 or not 7


there are 6 ways to get 7 out of 36 possible outcomes ___ so the probability of 7 (on any roll) is 6/36 or 1/6
___ P(s) = 1/6 , P(n) = 5/6


the expansion is ___[P(s) + P(n)]^3 = s^3 + 3s^2n + 3sn^2 + n^3


at least two means the sum of the first two terms (with s^3 and s^2)


P = (1/6)^3 + [3 * (1/6)^2 * (5/6)]