<PRE><B>Question 603457</B>
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Try the Binomial Distribution again.  Number of successes: 3, Number of trials: 3, P(success) on one trial = *[tex \LARGE \frac{16}{20}\ =\ \frac{4}{5}], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P_3(3,0.8))\ =\ {{3}\choose{3}}\left(0.8\right)^3\left(0.2\right)^{0}]


Hint:  *[tex \LARGE {{n}\choose{n}}\ =\ {{n}\choose{0}}\ =\ 1] and *[tex \LARGE a^0\ =\ 1]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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