<PRE><B>Question 603462</B>
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The sum of the logs is the log of the product, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log(3x)\ =\ \log\left(4(x\ -\ 1))]


Two logs to the same base are equal if and only if their arguments are equal.  Set the two arguments equal and solve.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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