Question 603200
 <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
If this is laid out properly...check the sign
*[tex \LARGE \ \ log (x/(x-1)) + log ((x+1)/x)- log(x^2-1) ]
log {{{((x/(x-1))*((x+1)/x))/(x-1)(x+1)) }}} = log{{{(x-1)^highlight(-2)}}}
Rules governing Logarithms
*[tex \large\ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ] ****
*[tex \large\ \ log_bx - log_by = log_b(x/y) ] *****
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]