Question 603216
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Hi,
*[tex \LARGE \ \ log (2xy) - log (x) = log(2xy/x)=log(2y) ]

Rules governing Logarithms
*[tex \large\ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ] *****
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]