Question 603262
Container A, of volume a, is half full.
Container B, of volume b, is one third full.
container C, of volume c, is empty.
If all the water in the containers is divided equally among the containers,What part of container C will be full?
:
the total amt of water
{{{1/2}}}a + {{{1/3}}}b + 0c
:
Divide the total amt by 3
{{{1/3}}}({{{1/2}}}a + {{{1/3}}}b) = {{{1/6}}}a + {{{1/9}}}b
:
Container C fractional part full
{{{((1/6)a + (1/9)b)/c}}}
Get rid of the fractions, multiply by {{{18/18}}}
{{{18/18}}}*({{{((1/6)a + (1/9)b)/c}}}) = {{{(3a + 2b)/(18c)}}}