Question 603273
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Hi,
a. 32 = 2^5    |*[tex \large\ \ log_2(32) = 5]
b. 1/125 = 25^–3/2  {{{log(25)(1/125) = -3/2}}}
c. 12 = 144^1/2    {{{log144(12) = 1/2}}}

 a. log3 81 = 4  {{{3^4 = 81}}}
 b. log10 0.0001 = –4 {{{10^(-4) = .0001}}}
 c. log3 (1/243)= -5 {{{3^(-5) = 1/243}}}

Rules governing Logarithms
*[tex \LARGE \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]