Question 603315
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
polynomial with a degree of 4 has zeros at x=-2, x= 2  and  x=0 (two) 
f(x) = a(x+2)(x-2)(x-0)(x-0)
f(x) = ax^2( x^2 - 4)
f(1) = -3a = 2
        a = (-2/3)
f(x) = (-2/3) x^2( x^2 - 4)

{{{drawing(300,300,   -10,10,-10,10,  
 grid(1),
circle(0, 0,0.4),
circle(-2, 0,0.4),
circle(2, 0,0.4),
graph( 300, 300, -10,10,-10,10,0,(-2/3) x^2( x^2 - 4) ))}}}