Question 603320
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
cubic polynomial has zeros at x=1 x=-2 x=2 
f(x) = a(x-1)(x-2)(x+2)
f(x) = a(x^3-x^2-4x+4)
y intercept of 2
f(0) = 4a = 2
        a = .5
f(x) = .5(x-1)(x-2)(x+2)
{{{drawing(300,300,   -10,10,-10,10,  
 grid(1),
circle(1, 0,0.4),
circle(-2, 0,0.4),
circle(2, 0,0.4),
graph( 300, 300, -10,10,-10,10,0,.5(x-1)(x-2)(x+2)))}}}