Question 603206
NOTE:
I may be misinterpreting "5xsqrt" and or "10x to the sixth power"
The conventional way to type square roots and powers is like this:
{{{sqrt(x)}}}=sqrt(x) , {{{10x^6=10*x^6}}}=10x^6=10*x^6 , and {{{(10x)^6}}}=(10x)^6
We use ^ to indicate that the exponent is written higher than the rest; we use * to indicate multiplication, and we use sqrt( ) when we mean square root, with whatever is under the radical sign in the brackets.
 
IF THE PROBLEM WAS {{{base=10x^6}}} and {{{height=5sqrt(x)}}}
You must know that the area of a triangle can be calculated as 1/2 times base, times height.
{{{area=(1/2)(10x^6)(5sqrt(x))}}}
That can be simplified somewhat.
Because of the associative and commutative properties, numbers and expressions that are multiplied together can be multiplied in any order, grouping them in any way, with the same result.
You have {{{1/2}}} {{{10}}} {{{x^6}}} {{{5}}} and {{{sqrt(x)}}} multiplied together, grouped by brackets in a certain way. The resulting product is the same if the grouping and order is changed to a more convenient way:
{{{(1/2)(10x^6)(5sqrt(x))=((1/2)*10*5)(x^6*sqrt(x))}}}
So {{{area=((1/2)*10*5)(x^6*sqrt(x))}}}
We can do the indicated multiplication, and there are different ways to express it, but I like
{{{area=25x^6*sqrt(x)}}} or the same thing without the dot between {{{x^6}}} and {{{sqrt(x)}}}.
 
IF THE PROBLEM WAS {{{base=(10x)^6}}} and {{{height=5sqrt(x)}}}
you must know that {{{(10x)^6=10^6*x^6=1000000x^6}}}
but the rest of the calculation is done in a similar way.