Question 56096
First graph the equation 2x+3y = 6, which has x intercept: y=0, x= 3; and y intercept: x=0, y=2.  Draw a DOTTED line, since you do NOT want to include the line, and shade the area ABOVE the line, since it is a POSITIVE Y coefficient, with a ">" symbol.  Here is the line:
{{{graph (300,300,-6,6,-6,6, (-2x/3)+2)}}}

You will have to make this a DOTTED line and SHADE ABOVE THE LINE.  Unfortunately, I don't know how to do this in algebra.com notation!


R^2 at SCC