Question 603088
Find the vertex of the following quadratic function, and find any intercepts. Also determine the graph of the function. 
f(x)= x^2-6x+10
-----
Complete the square:
f(x) = x^2-6x+9 + 10-9
---
f(x) = (x-3)^2 + 1
---
Vertex: (3,1)
---
x-intercepts(s)
Solve (x-3)^2 + 1 = 0
None
----
y-intercepts
Let x = 0; then y = 10
-------------------------------
Cheers,
Stan H.
===============================