Question 603088
Find the vertex of the following quadratic function, and find any intercepts. Also determine the graph of the function. 
f(x)= x^2-6x+10
**
complete the square
y=(x^2-6x+9)+10-9
y=(x-3)^2+1
vertex: (3,1)
..
x-intercepts
set y=0
(x-3)^2+1=0
(x-3)^2=-1
x-intercepts: none
..
See graph below:
{{{ graph( 300, 200, -10, 10, -10, 10,x^2-6x+10) }}}