Question 56082
How would I simplify this rational expression that is in fraction form?
{{{(9-b^2)/(b^2-b-6)}}}
You're almost right...
{{{(-(b^2-9))/(b^2-b-6)}}}
{{{(-((b+3)(b-3)))/((b-3)(b+2))}}}
{{{(-((b+3)*cross(b-3)))/(cross(b-3)*(b+2))}}}
{{{(-(b+3))/(b+2)}}}
{{{highlight(-(b+3)/(b+2))}}}
Happy Calculating!!!