Question 602972
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Hi,
{{{3y^-1(5x^2y^2)= 15x^2y}}}

 {{{a^0 = 1}}}
{{{(a^p)^q = a^(p*q)}}}
{{{root(a,p)*root(a,q) = root(a,p*q)}}}
{{{x^m/x^n=x^(m-n)}}}
{{{( x^m )( x^n ) = x^( m + n )}}} *****