Question 602814
12y-2xy-2x(^2)y= -2y(x^2+x-6)=-2y(x-2)(x-3)
6y-4xy-2x^2y= -2y(x^2+2x-3)=-2y(x+3)(x-1)
divide both : 
12y-2xy-2x(^2)y
------------          = (x-2)/(x-1)
6y-4xy-2x^(2)y 


 20y^(2)-45 = 5(4y^2-9)=5(2y-3)(2y+3)
10y^(2)-5y-15 = 5(2y^2-y-3)= 5(2y-3)(y+1)
divide both 

20y^(2)-45
-----------    = (2y+3)/(y+1)
10y^(2)-5y-15