Question 602646
What is the cos,sin and tan of x=sqrt6 and y=-sqrt2.
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{{{r = sqrt(x^2 + y^2) = sqrt(8)}}}
sin = y/r = -sqrt(2)/sqrt(8) = -1/2
cos = x/r = sqrt(6)/sqrt(8) = sqrt(3)/2
tan = y/x = -sqrt(3)/3