Question 602596
I need help understanding a couple problems. 
1)Find the inverse function, f^ -1(x) for (2/3)x – 1/4
y = (2/3)x - 1/4
1st: Interchange x and y:
x = (2/3)y - 1/4
2nd: solve for "y":
(2/3)y = x+(1/4)
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y = (3/2)x + (3/8)
f^-1(x) = (3/2)x+(3/8)
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2) Find the inverse function f ^-1(x), for -5x + 6
y = -5x+6
1st: Interchange x and y:
x = -5y+6
2nd: Solve for "y":
5y = -x+6
y = (-1/5)x + (6/5)
f^-1(x) = (-1/5)x + (6/5)
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3) Evaluate the equation below at x = -2, -1, 0, 1, 2, 3,and 4. 
y = x^3 - 3x^2 - 2x + 1 graph and plot points.
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I'll leave the evaluating to you.
{{{graph(400,400,-10,10,-10,10,x^3-3x^2-2x+1)}}}
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Cheers,
Stan H.