Question 602515
I'm assuming you want to factor this.




{{{16x^2-36}}} Start with the given expression.



{{{(4x)^2-36}}} Rewrite {{{16x^2}}} as {{{(4x)^2}}}.



{{{(4x)^2-(6)^2}}} Rewrite {{{36}}} as {{{(6)^2}}}.



Notice how we have a difference of squares {{{A^2-B^2}}} where in this case {{{A=4x}}} and {{{B=6}}}.



So let's use the difference of squares formula {{{A^2-B^2=(A+B)(A-B)}}} to factor the expression:



{{{A^2-B^2=(A+B)(A-B)}}} Start with the difference of squares formula.



{{{(4x)^2-(6)^2=(4x+6)(4x-6)}}} Plug in {{{A=4x}}} and {{{B=6}}}.



So this shows us that {{{16x^2-36}}} factors to {{{(4x+6)(4x-6)}}}.



In other words {{{16x^2-36=(4x+6)(4x-6)}}} for all values of x.