Question 602517
{{{8y-5=5(y-1)+3y}}} Start with the given equation.



{{{8y-5=5y-5+3y}}} Distribute.



{{{8y-5=8y-5}}} Combine like terms on the right side.



{{{8y=8y-5+5}}} Add {{{5}}} to both sides.



{{{8y-8y=-5+5}}} Subtract {{{8y}}} from both sides.



{{{0y=-5+5}}} Combine like terms on the left side.



{{{0y=0}}} Combine like terms on the right side.



{{{0=0}}} Simplify.



Since this equation is <font size=4><b>ALWAYS</b></font> true for value of 'y', this means 'y' can equal any number. 



So there are an infinite number of solutions.