Question 602473
Note: All logs shown below are in base 'a'


log(144)


log(16*9)


log(16)+log(9)


log(16)+log(3^2)


log(16)+2*log(3)


2.846+2*0.573


2.846+1.146


3.992



Answer: So <img src="http://latex.codecogs.com/gif.latex?\Large \log_{a}(144) = {\color{red} 3.992} \ \text{where } \log_{a}(16)=2.846 \ \text{ and } \log_{a}(3)=0.573" title="x" />