Question 602468
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Hi,
Let x and (x+1) represent the Two consecutive positive integers
Question states***
{{{(x+1)^2 + 4x = 28}}}
Solving for x
 x^2 + 2x + 1 + 4x = 28
 x^2 + 6x -27 = 0
(x-3)(x+9)= 0
x = 3 
the Two consecutive positive integers are 3,4 
CHECKING our Answer***
 16 + 12 = 28