Question 602424
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Hi,

*[tex \large\ \ nlog_bx = log_b(x^n) ]

*[tex \LARGE\ \ log_5(49) - log_5(x+3) = log_5(49/(x+3)= 2 ]
{{{5^2 = 49/(x+3)}}}
x+3 = 49/25
  x = - 26/25

Note the following rules governing Logarithms:
*[tex \large \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]