Question 602220
2(3x+4)-4x(3x+4)=0      

-12x^2-10x+8=0 

/-2
6x^2+5x-4=0

Find the roots of the equation by quadratic formula							
							
a=	6	,	b=	5	,	c=	-4
							
b^2-4ac=	25	+	96				
b^2-4ac=	121						
{{{	sqrt(	121	)=	11	}}}		
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(	-5	+	11	)/	12		
x1=	0.50						
{{{x2=(-b-sqrt(b^2-4ac))/(2a)}}}							
x2=(	-5	-11	) /	12			
x2=	-1.33						
					
	0.5 & -1.33 are the roots of the equation						
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