Question 602070
x1		y1	x2	y2										
-3		-2	1	-2										
														
slope m =		(y2-y1)/(x2-x1)												
(	-2	-	-2	)/(	1	-	-3	)						
(	0	/	4	)  										
m=		0    						 						
The required line passes through both the points. So we select one point and plug it with the slope 														
Plug value of  the slope  and point			(	-3	,	-2	) in							
Y	=	m	x	+	b							OK		
-2.00	=	0    	*	-3	+	b								
-2.00	=	-0    	+	b										
b=	-2    	+	-2    											
b=	0      													
So the equation  will be														
Y 	=	-2    									
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