<PRE><B>Question 602068</B>
A has a 12 min lead on B ___ 12 min is 1/5 hr (12/60)


A is traveling 80 mph, so 1/5 hr is 16 mi (80 * 1/5)


B is catching A at 10 mph (90 - 80)


it will take B 1.6 hr to catch A (16 / 10) ___ this is from the time that B passes the station


equation-wise; the distances are equal when B catches up, and A has 1/5 hr head start


90t = 80(t + 1/5)


the question asks what time, so t must be added to 9:32 PM</PRE>