Question 601817
This question is a reasoning question which can be solved by deep thinking.
      Solution:
the type of animal in d kennel is 3, let dis 3 animals be represented by a, b, c. Let d first animal be a, & d second animal be b, & d third animal be c. From d question, let d 1st integer increased by twice the 2nd & exceed d 3rd by 10.
Step 2: since d 1st integer increased twice d 2nd = 2a : b
Step 3: since d 2nd exceed the third by 10 = 10b : c
Step 4: Recall that  the question state the 1st is increased twice the second = 2*10=20a.
Step 5: Each dog will have 20 : 10 : 1.