Question 601556
log2(3x+2)-log4x=3
convert to log base 2
log2(3x+2)-log2(x)/log2(4)=3
log2(4)=2
log2(3x+2)-log2(x)/2=3
LCD=2
2log2(3x+2)-log2(x)=6
place under single log
log2[(3x+2)^2/x)]=6
convert to exponential form
2^6=(3x+2)^2/x
64=(9x^2+12x+4)/x
64x=9x^2+12x+4
9x^2-52x+4=0
solve by quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
a=9, b=-52, c=4
x=.078
or
x=5.700