Question 601557
A rocket is fired in te air from the top of a building that is 200 feet tall. the initial velocity of the rocket is 600 feet per second. 
.
a. write the height function 
h(t) = -32t^2 + 600t + 200
.
b. When does the rocket reach it maximum height
at the vertex:
t = -b/(2a)
t = -600/(2(-32))
t = -600/(-64)
t = 9.375 seconds
.
c. What is the rocket's maximum height d. when does it hit the ground?
plug answer from b. into the equation:
h(t) = -32t^2 + 600t + 200
h(9.375) = -32(9.375)^2 + 600(9.375) + 200
h(9.375) = 3012.5 feet