<PRE><B>Question 601499</B>
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I think you mean &lt;i&gt;if the &lt;b&gt;sum of the measures of the angles of the &lt;/b&gt;triangle is 180 degree&lt;b&gt;s&lt;/b&gt;&lt;/i&gt;.  Well, in the first place why say &lt;b&gt;&lt;i&gt;If&lt;/i&gt;&lt;/b&gt; -- what else could it be?  Hence, the condition on the problem is redundant.


Let *[tex \Large x] represent the measure of angle A.  Then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 4x\ +\ 5x\ -\ 20\ =\ 180]


Solve for *[tex \Large x], then calculate *[tex \Large 4x], and *[tex \Large 5x\ -\ 20].  Check your work by adding the results for the three angles to verify that the sum is 180.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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