Question 601470
Determine the vertex of the parabola. 
f(x) = x^2 - 8x + 17
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One way:
Complete the square:
x^2 - 8x + 16 + 17-16 = y
(x-4)^2 = y-1
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Vertex at (4,1)
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Another way:
Vertex occurs where x = -b/(2a) = 8/2 = 4
f(4) = 16-32+17 = 1
Vertex at (4,1)
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{{{graph(400,400,-10,10,-10,10,x^2-8x+17)}}}
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Cheers,
Stan H.