Question 601259
{{{x^2+y^2=17}}}

(x+y)=1

y= 1-x

{{{x^2+(1-x)^2=17}}}

{{{x^2+1-2x+x^2=17}}}

{{{2x^2-2x+1=17}}}

{{{2x^2-2x-16=0}}}

/2
{{{x^2-x-8=0}}}


Find the roots of the equation by quadratic formula							
							
a=	1	,	b=	-1	,	c=	-8
							
b^2-4ac=	1	+	32				
b^2-4ac=	33						
{{{	sqrt(	33	)=	5.74	}}}		
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(	1	+	5.74	)/	2		
x1=	3.37						
{{{x2=(-b-sqrt(b^2-4ac))/(2a)}}}							
x2=(	1	-5.74	) /	2			
x2=	-2.37						

When x= 3.37 y = -2.37 

When x= -2.37 y=3.37

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