Question 600987
the length of rectangle is 14 feet more than the width. the perimeter of the rectangle is 132 feet. Find the width

First steps first: write equation A to model your problem.

perimeter = 2lengths + 2widths
{{{p = 2L + 2W}}}
your perimeter equals 132 ft. Therefore, equation A is: {{{132 = 2L + 2W}}}

We know that the length is 14 ft more than the width. Write equation B to model this: {{{L = W + 14)

Now combine your two equations, substituting B into A: 
{{{132 = 2(W + 14) + 2W)}}}

Eliminate your parenthesis by multiplying: {{{132 = 2W + 28 + 2W}}}

Simplify: {{{132 = 4W + 28}}}

Isolate the variable (4W) by subtracting 28 from both sides: {{{104 = 4W}}}

divide both sides by 4 to determine the value of w: {{{104/4 = 4W/4}}}
simplify: {{{26 = W}}}

Your width is 26 ft. If you want to find the length, which you didn't ask for, add 14 to 26 to find the length ( 40 ft.)

I hope this helps!