Question 600930
John has t tapes and James has ten tapes more than John.
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Then we add 10 to t and get t+10 tapes that James has.

Answer:  James has t+10 tapes
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b.  John gives James 14 of his tapes.  
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So we subtract 14 from the number of tapes that John has,
so John now has t-14 tapes.

And we must add those 14 tapes to the number of tapes that James has.
So James now has t+10+14 tapes which is the same as t+24 tapes.  
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James now has twice as many tapes as john has.
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So the t+24 tapes that James has must equal to 2 times the t-14 tapes
which John has.  So we make this equation:

       t+24 = 2(t-14)

write an algebraic expression to represent the amount eavh person has

We solve that equation:

We use the distributive principle on the right side to remove the
parentheses:

       t+24 = 2(t-14)
       t+24 = 2t-28

We add -2t to both sides

   t+24 - 2t = 2t-28 - 2t

We combine like terms:

     -t + 24 = -28

We add -24 to both sides

-t + 24 - 24 = -28 - 24 

          -t = -52

The coefficient of t on the left is -1

         -1t = -52    

We divide both side of the equation by -1

         {{{(-1t)/(-1)}}} = {{{(-52)/(-1)}}}

           t = 52

John started out with 52 tapes and James started out with 10 more, or 62


Therefore John started out with 52, and James had t+10, or 52+10, or 62.

Then John gave James 14 tapes.  Then John had 52-14 or 38 tapes left.  And
James then had 62+14 or 76 tapes,

And if you multiply 38 by 2 you get 76.  

Edwin</pre>