Question 600838
if 3x^2 - 4x + 7 = 0, then (x - 2/3)^2 = ???

divide by 3
{{{x^2-(4/3)x +(7/3)=0}}}

Complete the square by adding 4/9 on both sides


{{{x^2-2(1)(2/3) +4/9 +(7/3)=4/9}}}


{{{(x-(2/3))^2+7/3 = 4/9}}}

{{{(x-(2/3))^2= -7/3 +4/9}}}


{{{ (x-(2/3))^2= (-21+4)/9}}}


{{{(x-(2/3))^2=(-17/9)}}}