Question 55967
Remember that the slope-intercept form is {{{y=mx+b}}}. On these, you just have to find {{{m}}} and {{{b}}}. Also remember that {{{m = (y2-y1)/(x2-x1)}}}
Let's find {{{m}}} for your first problem:
{{{m = (y2-y1)/(x2-x1)}}}
{{{m = (-4--2)/(3-6)}}}
{{{m = (-2)/-3}}}
{{{m = 2/3}}}

Ok, now we have to find {{{b}}}. Our equation so far is {{{y = (2/3)x + b}}}. If we plug one of the points (doesn't matter which one...) in for {{{x}}} and {{{y}}}, we can solve for {{{b}}}.
{{{y = (2/3)x + b}}}
Plugging in (3,-4)
{{{-4=(2/3)(3)+b}}}
{{{-4=2+b}}}
{{{-6 = b}}}
Alright. Our equation is {{{y = (2/3)m - 6}}}!!!

There. I did the first one. You can do the second one