Question 55967
Question 1:
    The formula with a line that has a slope of m and a y-intercept (the value of y where the line crosses the y-axis) of b is
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y = mx + b
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To find the slope, m, of the line is the change in y divided by the change in x.
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x1= 6 ; y1= -2
x2= 3 ; y2= -4
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{{{m = (y2-y1) / (x2-x1)}}}
{{{m = (-4 - -2) / (3 - 6)}}}
{{{m= (-2)/-3}}}
{{{m= 2/3}}}
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Now, to find the y-intercept, b, use one of the points to get the x and y values, and solve for b.
Remember: 
x1= 6 ; y1= -2    
x2= 3 ; y2= -4
{{{m=2/3}}}

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y1 = mx1 + b              
b = y1 - mx1                        
b = -2 - {{{2/3}}} (6)
b = -6 
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Now that we know the slope, m = {{{2/3}}}, and the y-intercept, b = -6, we can write the equation of the line:
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y= {{{(2/3)x -6}}}
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Question 2:
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We would do the same process:
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x1= -8 ; y1= 2
x2= 2  ; y2= 6
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{{{m = (y2-y1) / (x2-x1)}}}
{{{m = (6 - 2) / (2 - -8)}}}
{{{m= 4/10}}}
{{{m= 2/5}}}
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y1 = mx1 + b              
b = y1 - mx1 
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{{{b = 2 - (2/5)(-8)}}}
b = 5.2
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Now that we know the slope, {{{m = (2/5)}}}, and the y-intercept, b = 5.2, we can write the equation of the line:
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{{{y= (2/5)x+5.2}}} 
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**Remember to always check your answer**