Question 600341
Xx+yy=x+2
x^2+y^2=x+2
x^2-x+y^2=2
complete the square
(x^2-x+1/4)+y^2=2+1/4
(x-1/2)^2+y^2=9/4
This is an equation of a circle with center at (1/2,0) and radius=√(9/4)=3/2
Its standard form: (x-h)^2+(y-k)^2=1, (h,k)=(x,y) coordinates of center, r=radus
see graph below:
y=±(-x^2+x+2)^.5

{{{ graph( 300, 300, -4, 4, -4, 4,(-x^2+x+2)^.5,-(-x^2+x+2)^.5) }}}