Question 600423
Given that angleC= 45 degree, a=20 and b=17. What is the length of side c in angleABC to the nearest tenth?
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Use Law of cosines: 
c^2=a^2+b^2-2abcosC
c^2=20^2+17^2-2*20*17cos45º
c^2≈331.78
c=√331.78≈18.2