Question 600343
{{{2m^2+9m+7=3}}}
or {{{2m^2+9m+7-3=0}}}
or {{{2m^2+9m+4=0}}}
Now this quadratic equation can be solved using the formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

But I solve it by splitting its middle term

So {{{2m^2+9m+4=0}}} can be written as 
{{{2m^2+8m+m+4=0}}}
OR {{{( 2m^2+8m ) + ( m+4 )=0}}}
OR {{{2m*( m+4 ) + 1*( m+4 )}}}
OR {{{( m+4 )( 2m+1 )=0}}}

Now either (m + 4) = 0 OR (2m + 1) = 0
solving these equations we get,
m = -4 & m = -1/2