Question 600332
log base 4 (x+1) - log base 4x=3
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log4(x+1) - log4(x) = 3
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log4[(x+1)/x] = 3
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(x+1)/x = 4^3
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(x+1)/x = 64
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x+1 = 64x
63x = 1
x = 1/63
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Cheers,
Stan H.