<PRE><B>Question 55921</B>
Write an equation in slope-intercept form of a line with the following characteristics. Perpendicular to the graph of: y = 3/2x-3 with a y-intercept of 5. 
The given line has a slope of (3/2).  Your line will have a slope
of -2/3 and a y-intercept of 5.
Your equation is y=(-2/3)x+5
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Write an equation in slope-intercept form of a line with the following characteristics: parallel to the graph of: -4x+3y=12 and passes through the origin.
The given line has a slope of 4/3. The line parallel will have the same
slope.  Since your line passes through the origin the y-intercept is 0.
The equation you want is y=(4/3)x
Cheers,
Stan H.

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